Tuesday, April 1, 2014

Evaluate Reverse Polish Notation @LeetCode

Evaluate the value of an arithmetic expression in Reverse Polish Notation.
Valid operators are +-*/. Each operand may be an integer or another expression.
Some examples:
  ["2", "1", "+", "3", "*"] -> ((2 + 1) * 3) -> 9
  ["4", "13", "5", "/", "+"] -> (4 + (13 / 5)) -> 6

package leetcode;
import java.util.Stack;
/**
* Solution: Use stack store numbers and calculate when meets operator.(get number from stack and store result into stack)
* Use string.contains(substr) to check operator
* Don't forget break!!!
* @author jeffwan
* @date Apr 1, 2014
*/
public class EvalRPN {
public int evalRPN(String[] tokens) {
if (tokens == null || tokens.length == 0) {
return 0;
}
Stack<Integer> stack = new Stack<Integer>();
String operators = "+-*/";
for (String token : tokens) {
if (!operators.contains(token)) {
stack.push(Integer.parseInt(token));
continue;
}
int a = stack.pop();
int b = stack.pop();
switch(token.charAt(0)) {
case '+':
stack.push(b + a);
break;
case '-':
stack.push(b - a);
break;
case '*':
stack.push(b * a);
break;
case '/':
stack.push(b / a);
break;
}
}
return stack.pop();
}
// My ways is not very clear
public int evalRPN2(String[] tokens) {
Stack<String> stack = new Stack<String>();
for (int i = 0; i < tokens.length; i++) {
System.out.println(stack);
if (isNumberic(tokens[i])) {
stack.push(tokens[i]);
} else {
int number1 = Integer.parseInt(stack.pop());
int number2 = Integer.parseInt(stack.pop());
// deal with the operator
int result = calculate(number2, number1, tokens[i]);
stack.push(Integer.toString(result));
}
}
return Integer.parseInt(stack.peek());
}
public int calculate(int number1, int number2, String operator) {
switch (operator.charAt(0)) {
case '+':
return number1 + number2;
case '-':
return number1 - number2;
case '*':
return number1 * number2;
case '/':
return number1 / number2;
default:
return 0;
}
}
public boolean isNumberic(String number) {
return number.matches("-?\\d+(\\.\\d+)?");
}
}
view raw EvalRPN.java hosted with ❤ by GitHub

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